Using an elastic neutron scattering technique under a pulsed magnetic field up to 30 T, we determined the magnetic structure in the half-magnetization plateau phase in the spinel CdCr(2)O(4). The magnetic structure has a cubic P4(3)32 symmetry, which is the same as that observed in HgCr(2)O(4). This suggests that despite their different zero-field ground states a universal field-induced spin-lattice coupling mechanism is at work in the Cr-based spinels.