The QCD sum rule method is applied to derive a formula for the rho, omega,<br />
phi meson-nucleon spin-isospin-averaged scattering lengths<br />
$a_{\rho,\omega,\phi}$. We found that the crucial matrix elements are<br />
$\langle\bar{q}\gamma_\mu D_\nu q\rangle_N$ ($q=u,d$) (twist-2 nucleon matrix<br />
element) for $a_{\rho,\omega}$ and $m_s\langle\bar{s}s\rangle_N$ for $a_\phi$,<br />
and obtained $a_\rho =0.14\pm 0.07$ fm, $a_\omega =0.11\pm 0.06$ fm and $a_\phi<br />
=0.035\pm 0.020$ fm. These small numbers originate from a common factor<br />
$1/(m_N+m_{\rho,\omega,\phi})$. Our result suggests a slight increase ($&lt; 60$<br />
MeV for $\rho$, $\omega$, and $&lt;15$ MeV for $\phi$) of the effective mass of<br />
these vector mesons in the nuclear matter (in the {\it dilute} nucleon gas<br />
approximation). The origin of the discrepancy with the previous study was<br />
clarified.