Radical anion salts of metal phthalocyanines {cryptand[2,2,2](Na+)}[M(Pc center dot 3-)](center dot-)center dot C6H4Cl2 (M = Cu-II (1), Pb-II (2), (VO)-O-IV (3) and (SnCl2)-Cl-IV (4)) and {cryptand[2,2,1](Na+)}[(SnCl2)-Cl-IV(Pc center dot 3-)](center dot-)center dot C6H4Cl2 (5) have been obtained as single crystals. Phthalocyanine planes form channels to accommodate the cryptand[2,2,2](Na+) cations and solvent C6H4Cl2 molecules in 1-3. Nearly square phthalocyanine layers are formed in salts 4 and 5, which are parallel to the ac plane and have an effective pp interaction between the Pc center dot 3- macrocycles. The using of smaller cryptand[2,2,1](Na+) cations in 5, instead of larger cryptand[2,2,2](Na+) cations in 4, allows one to obtain more closely packed Pc layers. Reduction in the salts was centered on the Pc macrocycles, providing alternation of the C-N (imine) bonds in Pc due to partial loss of aromaticity. New bands were also observed in the NIR spectra at 9461006 nm and the Soret and Q-bands were essentially blue-shifted in the spectra of the salts. The [CuII(Pc center dot 3-)](center dot)- and [(VO)-O-IV(Pc center dot 3-)](center dot-) radical anions contain paramagnetic Cu-II and (VO)-O-IV centers and the Pc center dot 3- radical trianions, both having a S = 1/2 spin state. These radical anions were nearly isolated in the salts. Weak antiferromagnetic coupling with a Weiss temperature (theta) of -2 K was observed in 1. The magnetic behavior of 3 was described by a modified singlettriplet model with a ferromagnetic exchange coupling of J/kB = 7.7 K within [(VO)-O-IV(Pc center dot 3-)]center dot- and theta = -1.3 K. The stronger antiferromagnetic coupling with a Weiss temperature of theta = -64 K was observed in 4 and was accompanied by the decrease of molar magnetic susceptibility below 35 K due to antiferromagnetic ordering of spins. The magnetic behavior of 4 was described using the Heisenberg model for quasi-square two-dimensional antiferromagnetic coupling between spins with an exchange interaction of J/kB = -18 K.